$\mathrm { X } ^ { 200 } \rightarrow \mathrm {~A} ^ { 110 } + \mathrm { B } ^ { 90 } + \text { Energy }$
The binding energy per nucleon for $\mathrm { X } ^ { 200 } , \mathrm {~A} ^ { 110 } , \mathrm {~B} ^ { 90 }$ are respectively 7.4 MeV, 8.2 MeV and 8.2 Mev. The energy released is
- A 200 MeV
- B 160 MeV
- C 110 MeV
- D 90 MeV
Show answer
Correct answer: B