Properties of Solids and Liquids — DPP 3

20 NEET questions from Properties of Solids and Liquids, with answers and explanations. Attempt it as a timed test to get scoring, accuracy breakdown and mistake tracking.

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1
The pressure of a medium is changed from $1.01 \times 10 ^ { 5 } \mathrm {~Pa}$ to $1.165 \times 10 ^ { 5 } \mathrm {~Pa}$ and change in volume is 10% keeping temperature constant. The bulk modulus of the medium is :-
  1. A $204.8 \times 10 ^ { 5 } \mathrm {~Pa}$
  2. B $102.4 \times 10 ^ { 5 } \mathrm {~Pa}$
  3. C $51.2 \times 10 ^ { 5 } \mathrm {~Pa}$
  4. D $1.55 \times 10 ^ { 5 } \mathrm {~Pa}$
Show answer & explanation

Correct answer: D

(Bulk Modulus) $\mathrm{K}=\frac{\Delta \mathrm{P}}{\Delta \mathrm{V} / \mathrm{V}}$
$=\frac{0.155 \times 10^{5}}{10 / 100}=1.55 \times 10^{5} \mathrm{~Pa}$
2
A vessel, whose bottom has round holes with diameter of 0.1 mm, is filled with water. The maximum height to which the water can be filled without leakage is :(S.T. of water = 75 dyne/cm}, g = 1000 cm/s$^{2}$)
  1. A 100 cm
  2. B 75 cm
  3. C 50 cm
  4. D 30 cm
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Correct answer: D

Properties of Solids and Liquids – NEET-7923
3
An aeroplane of mass $3 \times 10 ^ { 4 } \mathrm {~kg}$ and total wing area of 120 m$^{2}$ is in a level flight at some height. The difference in pressure between the upper and lower surfaces of its wings in kilopascals is (g = 10 m/s$^{2}$)
  1. A 2.5
  2. B 5.0
  3. C 10.0
  4. D 12.5
Show answer & explanation

Correct answer: A

Level flight means net vertical force is zero
∴ mg = ∆P × A
$\Delta \mathrm{P}=\frac{\mathrm{mg}}{\mathrm{A}}=\frac{3 \times 10^{4} \times 10}{120}=2.5 \times 10^{3} \mathrm{~Pa}=2.5 \mathrm{kPa}$
4
Spiders and insects move and run about on the surface of water without sinking because :
  1. A Elastic membrane is formed on water due to propery of surface tension
  2. B Spiders and insects are ligther
  3. C Spiders and insects swim on water
  4. D Spiders and insects experience up-thrust
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Correct answer: A

Elastic membrane is formed on the surface of water due to surface tension. This help's spider & insects to move and run on the surface of water.
5
Two drops of equal radius are falling through air with a steady velocity of 5 cm/s. If the two drops coalesce, then its terminal velocity will be -
  1. A $4 ^ { 1 / 3 } \times 5 \mathrm {~cm} / \mathrm { s }$
  2. B $4 ^ { 1 / 3 } \mathrm {~cm} / \mathrm { s }$
  3. C $5 ^ { 1 / 3 } \times 4 \mathrm {~cm} / \mathrm { s }$
  4. D $4 ^ { 2 / 3 } \times 5 \mathrm {~cm} / \mathrm { s }$
Show answer & explanation

Correct answer: A

Properties of Solids and Liquids – NEET-7873
6
Which law states that the magnitude of pressure within fluid is equal in all parts ?
  1. A Pascal's law
  2. B Gay-Lusac's law
  3. C Dalton's law
  4. D Boyle's law
Show answer & explanation

Correct answer: A

Pascal's law states that the magnitude of pressure within fluid is equal in all parts.
7
If the density of the material increase, the value of Young's modulus
  1. A increases
  2. B decreases
  3. C first increases, then decreases
  4. D first decreases, then increases
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Correct answer: A

When density increases, the mass of material increases; for the same strain, more stress is required. So Young's modulus increases.
8
In a surface tension experiment with a capillary tube water rises up to 0.1 m. If the same experiment is repeated on an artificial satellite which is revolving round the earth, water will rise in the capillary tube up to a height of
  1. A 0.1 m
  2. B 0.98 m
  3. C 9.8 m
  4. D full length of capillary tube
Show answer & explanation

Correct answer: D

Inside a satellite, water will rise upto the top level but sill not overflow.
Radius of curvature (R') increases in such a way that final height h' is reduced and given by $\mathrm{h}^{\prime}=\frac{\mathrm{hR}}{\mathrm{R}^{\prime}}$ (It is in accordance with Zurin's law).
9
Bernoulli's equation for steady, non-viscous, in-compressible flow expresses the
  1. A Conservation of angular momentum
  2. B Conservation of density
  3. C Conservation of momentum
  4. D Conservation of mechanical energy.
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Correct answer: D

Bernoulli's equation for steady, non-viscous, in-compressible flow expresses the conservation of energy.
10
Water from a tap emerges vertically downwards with an initial speed of 1.0 m/s. The cross-sectional area of the tap is 10$^{-4}$ m$^{2}$. Assume that the pressure is constant throughout the stream of water and that the flow is steady, the cross-sectional area of the stream 0.15 m below the tap is :-
  1. A $5.0 \times 10 ^ { - 4 } \mathrm {~m} ^ { 2 }$
  2. B $1.0 \times 10 ^ { - 4 } \mathrm {~m} ^ { 2 }$
  3. C $5.0 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$
  4. D $2.0 \times 10 ^ { - 5 } \mathrm {~m} ^ { 2 }$
Show answer & explanation

Correct answer: C

From Bernoulli equation
$\frac{1}{2} \rho v^{2}=\rho g h \quad \Rightarrow v=\sqrt{2 g h}=2 \mathrm{~m} / \mathrm{s}$
from equation of continuity A$_{1}$v$_{1}$ = A$_{2}$v$_{2}$
$A_{2}=\left(\frac{v_{1}}{v_{2}}\right) \times A_{1}=\left(\frac{1}{2}\right) \times 10^{-4}=5 \times 10^{-5} \mathrm{~m}^{2}$
11
A liquid drop of diameter D breaks into 27 tiny drops. The resultant change in energy is -
  1. A $2 \pi \mathrm { TD } ^ { 2 }$
  2. B $4 \pi \mathrm { TD } ^ { 2 }$
  3. C $\pi \mathrm { TD } ^ { 2 }$
  4. D None of these
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Correct answer: A

Properties of Solids and Liquids – NEET-7917
12
The velocity of falling rain drop attain limited value because of
  1. A surface tension
  2. B upthrust due to air
  3. C viscous force exerted by air
  4. D air current
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Correct answer: C

The velocity of falling rain drop attain limited value because of viscous force exerted by air.
13
'Torr' is the unit of :-
  1. A Pressure
  2. B Density
  3. C Volume
  4. D Flux
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Correct answer: A

Torr is the unit of pressure.
14
The excess pressure inside an air bubble of radius r just below the surface of water is p$_{1}$. The excess pressure inside a drop of the same radius just outside the surface is p$_{2}$. If T is surface tension, then
  1. A $p _ { 1 } = 2 p _ { 2 }$
  2. B $\mathrm { p } _ { 1 } = \mathrm { p } _ { 2 }$
  3. C $p _ { 2 } = 2 p _ { 1 }$
  4. D $\mathrm { p } _ { 2 } = 0 , \mathrm { p } _ { 1 } \neq 0$
Show answer & explanation

Correct answer: B

Excess pressure in air bubble just below the water surface.
$\mathrm{P}_{1}=\frac{2 \mathrm{~T}}{\mathrm{r}}$
Excess pressure inside a drop
$\mathrm{P}_{2}=\frac{2 \mathrm{~T}}{\mathrm{r}}$
So P$_{1}$ = P$_{2}$
15
A small drop of water falls from rest through a large height h in air. The final velocity is
  1. A almost independent of h
  2. B proportional to √h
  3. C proportional to h
  4. D inversely proportional to h
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Correct answer: A

Final velocity is terminal velocity which is independent from 'h'
$\mathrm{v}_{\mathrm{T}}=\frac{2 \mathrm{r}^{2}}{9} \frac{(\rho-\sigma)}{\eta} \mathrm{g}$
16
If the terminal speed of a sphere of gold (density = 19.5 kg/m$^{3}$) is 0.2 m/s in a viscous liquid (density = 1.5 kg/m$^{3}$), find the terminal speed of a sphere of silver (density = 10.5 kg/m$^{3}$$^{}$) of the same size in the same liquid.
  1. A 0.4 m/s
  2. B 0.133 m/s
  3. C 0.1 m/s
  4. D 0.2 m/s
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Correct answer: C

Properties of Solids and Liquids – NEET-7874
17
A water drop is divided into 8 equal droplets. The pressure difference between inner and outer sides of the big drop
  1. A will be the same as for smaller droplet
  2. B will be half of that for smaller droplet
  3. C will be one-forth of that for smaller droplet
  4. D will be twice of that for smaller droplet.
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Correct answer: B

Properties of Solids and Liquids – NEET-7919
18
Scent sprayer is based on
  1. A Charle's law
  2. B Archimede's principle
  3. C Boyle's law
  4. D Bernoulli's theorem
Show answer & explanation

Correct answer: D

Scent sprayer is based on Bernoulli's theorem.
19
A cylinder is filled with a liquid of density d upto a height h. If the beaker is at rest, then the mean pressure on the wall is :-
  1. A Zero
  2. B hdg
  3. C $\frac { \mathrm { h } } { 2 } \mathrm { dg }$
  4. D 2hdg
Show answer & explanation

Correct answer: C

d = Density
h = Height of water
A = Base cross-sectional area
P$_{Bottom}$ (pressure due to liquid) = hdg
P$_{Top}$ (pressure due to liquid) = dg(0) = 0
av. pressure $=\frac{\mathrm{P}_{\text {Bottom }}+\mathrm{P}_{\mathrm{Top}}}{2}=\frac{\mathrm{hdg}}{2}$
20
A false statement is :
  1. A Angle of contact $\theta < 90 ^ { \circ }$, if cohesive force < adhesive force $\times \sqrt { 2 }$
  2. B Angle of contact $\theta > 90 ^ { \circ }$, if cohesive force $>$ adhesive force $\times \sqrt { 2 }$
  3. C Angle of contact $\theta = 90 ^ { \circ }$, if cohesive force $=$ adhesive force $\times \sqrt { 2 }$
  4. D If the radius of capillary is reduced to half, the rise of liquid column becomes four times
Show answer & explanation

Correct answer: D

$\mathrm{h}=\frac{2 \mathrm{~T} \cos \theta}{\mathrm{r} \rho \mathrm{g}}$
If the radius of capillary is reduced to half, the rise of liquid column becomes two times because h ∝ $\frac{1}{r}$

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